How to select random label from an array

so have array, list of of 2 labels, "hellolabel", , "goodbyelabel" need able randomly select object array, in case 1 of 2 labels, , make them become visible, because in interface builder 2 labels checked hidden please :[

code:

    blah.h    uilabel *hellolabel;  uilabel *goodbyelabel;      @property (nonatomic, retain) iboutlet uilabel *hellolabel;  @property (nonatomic, retain) iboutlet uilabel *goodbyelabel;    -(ibaction)buttonpressed;    @end    blah.m    -(ibaction)buttonpressed {    nsarray *array = [[nsarray alloc] initwithobjects: hellolabel, goodbyelabel, nil];    //* select random object nsarray  "array"       //*set random object  *label.hidden = no;    //* how how how do    [array release];      

 

use array "objectatindex" access object in array list, in case 1 of label objects, set it's property, "sethidden" "no" hide it.

feed "objectatindex" integer "array objectatindex:2" show object array, in case want make random number, use "random() % x" function finds random number, x limit. in case, want use number "2" since have objects in array.

code:

 //*set random object  *label.hidden = no;  [[array objectatindex: (random() % 2)] sethidden: no];

a better way, instead of hard coding number 2 in random() function find the number of objects in array, using [array count] , use number instead. way if add more objects (more labels) array, won't have readjust random() function.

makes code more flexible , causes less potential bugs in future (like if change array size/number of items).

code:

 //* set random number range max number of objects  // array using [array count]  [[array objectatindex: (random() % [array count])] sethidden: no];

note there alternative ways of producing more true (less pseudo-)random numbers, won't go here.

 

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